To the Top
File:  root - text - article - 2020 - 02 - detect-linked-list-cycle.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 203 Views, 20095 Search Bots | 120 Words

Subscribe to Feed Burner | Browse | Archive
Hi, here's your problem today. This problem was recently asked by Uber:

Given a linked list, determine if the linked list has a cycle in it. For notation purposes, we use an integer pos which represents the zero-indexed position where the tail connects to.

Example:
Input: head = [4,3,2,1,0], pos = 1.
Output: true
The example indicates a list where the tail connects to the second node.


class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None

class Solution(object):
def hasCycle(self, head):
# Fill this in.

testHead = ListNode(4)
node1 = ListNode(3)
testHead.next = node1
node2 = ListNode(2)
node1.next = node2
node3 = ListNode(1)
node2.next = node3
testTail = ListNode(0)
node3.next = testTail
testTail.next = node1

print(Solution().hasCycle(testHead))
# True
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 203 Views, 20095 Search Bots | 120 Words Subscribe to Feed Burner

Related Articles

  1. Patterns for breaking down questions you haven
  2. Progess made
  3. Daily Interview Problem: Merge List Of Number Into Ranges
  4. Algorithm Interview Question: Find the Single Element in an Array of Duplicates
  5. Algorithm Interview: Permutations of numbers
  6. Batch Programming in XP
  7. Find Missing Numbers in an Array
  8. Invert a Binary Tree
  9. Daily Interview Question: Find Cycles in a Graph
  10. Daily Interview Problem: Word Ordering in a Different Alphabetical Order

Comments (0)

    Be the first one to comment this page !


Page Edited: May 11 2024 14:36:49 | RSS Subscription
How to Cook a Perfect Steak? | <meta name="robots" content="index, follow">